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Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
What you posted says it becomes (2)(12) clear as day.Originally Posted by ServeChilled81
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
umm no.
if you agree that 2(12) is multiplication
I'm asking you how do you justify multiplying, before you divide in the second step of the problem
What you posted says it becomes (2)(12) clear as day.Originally Posted by ServeChilled81
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
umm no.
if you agree that 2(12) is multiplication
I'm asking you how do you justify multiplying, before you divide in the second step of the problem
it becomes (2)(12), or 2(12), or 2x12, and since there are no addends in the parentheses, you do not distribute it's just multiplication, that's all the parentheses is nowOriginally Posted by BC2310
What you posted says it becomes (2)(12) clear as day.Originally Posted by ServeChilled81
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
umm no.
if you agree that 2(12) is multiplication
I'm asking you how do you justify multiplying, before you divide in the second step of the problemYou're on team2 and you don't even know it
it becomes (2)(12), or 2(12), or 2x12, and since there are no addends in the parentheses, you do not distribute it's just multiplication, that's all the parentheses is nowOriginally Posted by BC2310
What you posted says it becomes (2)(12) clear as day.Originally Posted by ServeChilled81
Originally Posted by ncmalko1
Serve chilled just won this arguments for the 2's. Nicely done my man.
2 WIN. CLOSE THE THREAD!
umm no.
if you agree that 2(12) is multiplication
I'm asking you how do you justify multiplying, before you divide in the second step of the problemYou're on team2 and you don't even know it
48÷2(9+3) wrote:
My buddy â sent me an email
Spoiler [+]
48÷2(9+3) wrote:
My buddy â sent me an email
Spoiler [+]
The 2nd part of what you posted says "Then perform the functions outside the parentheses on that quanity"Originally Posted by ServeChilled81
it becomes (2)(12), or 2(12), or 2x12, and since there are no addends in the parentheses, you do not distribute it's just multiplication, that's all the parentheses is nowOriginally Posted by BC2310
What you posted says it becomes (2)(12) clear as day.Originally Posted by ServeChilled81
umm no.
if you agree that 2(12) is multiplication
I'm asking you how do you justify multiplying, before you divide in the second step of the problemYou're on team2 and you don't even know it
repeat the order of op from the top.
The 2nd part of what you posted says "Then perform the functions outside the parentheses on that quanity"Originally Posted by ServeChilled81
it becomes (2)(12), or 2(12), or 2x12, and since there are no addends in the parentheses, you do not distribute it's just multiplication, that's all the parentheses is nowOriginally Posted by BC2310
What you posted says it becomes (2)(12) clear as day.Originally Posted by ServeChilled81
umm no.
if you agree that 2(12) is multiplication
I'm asking you how do you justify multiplying, before you divide in the second step of the problemYou're on team2 and you don't even know it
repeat the order of op from the top.