- Feb 18, 2008
- 2,804
- 82
What if I wrote it asOriginally Posted by snakeyes17
Since you & others seem to keep ignoring this.Originally Posted by do work son
Originally Posted by usainboltisfast
How credible do you really think you are when you stated that you dont need to solve/simplify whats in the parenthesis first?
are you going to disprove the proof he just showed?
A + B = B + A (check)
(Xa + Xb) = X(a+b) (check)
Z ÷ (Xa + Xb) can we factor out the X yes we can ---> Z ÷ X(a+b)
Yes, you can apply distribution. Distribution is an act of multiplication.
BUT they are not truly applicable to the problem at hand.
That last example is not correct. You would get z ÷ [X(a+b)].
If you had Z÷X(a+b) , the distribution is an act of multiplication.
BUT there is division first.
In that example, you would be distributing [Z÷X(a)]+[Z÷X(b)]
THAT IS HOW DISTRIBUTION WORKS!
There is division first. It has to be included in this distribution.
IT IS FACT.
[48÷2(9)]+[48÷2(3)]
That is how you distribute. You follow order of operations, division and then multiplication within each bracket.
[24(9)]+[24(3)]
216+72 = 288
Z ÷ (Xa + Xb)
tell me what this equation is once the X is factored out of the parenthesis