48÷2(9+3) = ???

[greenranger]

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

 

[klipschorn]

team 288.

[h3]48÷2(9+3) = [complete the parenthesis first]
[/h3]48÷2(12) = [at this point, you have both division and multiplication, you have to evaluate from left to right]

24(12) = 288 [therefore, 288]

 

[klipschorn]

team 288.

[h3]48÷2(9+3) = [complete the parenthesis first]
[/h3]48÷2(12) = [at this point, you have both division and multiplication, you have to evaluate from left to right]

24(12) = 288 [therefore, 288]

 

[do work son]

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

 

[do work son]

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

 

[kingcrux31]

Originally Posted by Iron Mike

king krux should be suspended for trolling

Oh yeah?


Again...



If you still don't get it then I don't know anymore.

You should really call your school and ask them to explain.

 

[kingcrux31]

Originally Posted by Iron Mike

king krux should be suspended for trolling

Oh yeah?


Again...



If you still don't get it then I don't know anymore.

You should really call your school and ask them to explain.

 

[hankmoody]

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"


http://www.purplemath.com/modules/orderops2.htm

I posted this link over 40 pages ago... they don't get it. I agree with biggie62's rationale too.

 

[hankmoody]

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"


http://www.purplemath.com/modules/orderops2.htm

I posted this link over 40 pages ago... they don't get it. I agree with biggie62's rationale too.

 

[10littlefigures]

@@@% distributive property 288

 

[kingcrux31]

Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

Quoted  because I know these Math trolls will ignore this again.

 

[10littlefigures]

@@@% distributive property 288

 

[kingcrux31]

Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

Quoted  because I know these Math trolls will ignore this again.

 

[the yes guy]

Implicit multiplication is not an agreed upon mathematics standard.

 

[the yes guy]

Implicit multiplication is not an agreed upon mathematics standard.

 

[blackmambakb24]

79 pages.. wow..

 

[blackmambakb24]

79 pages.. wow..

 

[thehealthinspector]

Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2

 

[thehealthinspector]

Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  

"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2

 

[rocky437]

Again, just so its even more clear...

The distributive property of multiplication CLEARLY states that the 2(9+3) is an entire term and CANNOT be broken up. 2(9+3) follows the distributive property which can be rewritten as (2*9+2*3). Let me repeat the 2 outside of the parenthesis follows the distributive property of multiplication and must be factored and simplified before performing any other operations on it.

So this can be rewritten as:
48 / (2*9 + 2*3)

Which leaves us with

48 / 24 = 2

Answer = 2.

Lastly for those using Google or any other online calculator. These do not understand many theorems or properties so you must explicitly explain what you mean. There is a difference between 48 / 2 *(9+3) and 48 / 2(9+3). The first notation reads 48 / 2 * 1(9+3) while the second reads 48 / (2*9+2*3). Be very careful with your signs.

 

[rocky437]

Again, just so its even more clear...

The distributive property of multiplication CLEARLY states that the 2(9+3) is an entire term and CANNOT be broken up. 2(9+3) follows the distributive property which can be rewritten as (2*9+2*3). Let me repeat the 2 outside of the parenthesis follows the distributive property of multiplication and must be factored and simplified before performing any other operations on it.

So this can be rewritten as:
48 / (2*9 + 2*3)

Which leaves us with

48 / 24 = 2

Answer = 2.

Lastly for those using Google or any other online calculator. These do not understand many theorems or properties so you must explicitly explain what you mean. There is a difference between 48 / 2 *(9+3) and 48 / 2(9+3). The first notation reads 48 / 2 * 1(9+3) while the second reads 48 / (2*9+2*3). Be very careful with your signs.

 

[kingcrux31]

Originally Posted by TheHealthInspector

Originally Posted by do work son

Originally Posted by GreenRanger



"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2

Show me a Math problem with a Ã·(2(9+3)) 
This is just ridiculous. It's like saying divide AND multiply. 

 

[kingcrux31]

Originally Posted by TheHealthInspector

Originally Posted by do work son

Originally Posted by GreenRanger



"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm

the examples on that website pretty much seal the deal. team 2 ftw

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2

Show me a Math problem with a Ã·(2(9+3)) 
This is just ridiculous. It's like saying divide AND multiply. 

 

[bachelor frog]

http://i935.photobucket.c.../kingcrux31/IMG_4195.jpg

kingcrux31 how would you write this down as a faction :  [h3]48÷(2(9+3)) ? [/h3]

 

[bachelor frog]

http://i935.photobucket.c.../kingcrux31/IMG_4195.jpg

kingcrux31 how would you write this down as a faction :  [h3]48÷(2(9+3)) ? [/h3]